sherlock19
28.06.2019 •
Mathematics
The equation of a circle is given below ( x-20)^2 + (y-0.05)^2 =81 what is its center? what is its radius?
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Ответ:
So the center is at (20,.05) and the radius is 9
Step-by-step explanation:
The equation of a circle can be written in the form
(x-h) ^2 + (y-k) ^2 = r^2
where (h,k) is the center and r is the radius
Lets write our equation in that form
( x-20)^2 + (y-0.05)^2 =81
( x-20)^2 + (y-0.05)^2 =9^2
So the center is at (20,.05) and the radius is 9
Ответ:
see explanation
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
(x - 20)² + (y - 0.05)² = 81 is in this form
with centre = (20, 0.05) and r = = 9
Ответ:
i really don't understand what you are looking for can you please help so i can understand.
Step-by-step explanation: