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jillian0013
05.07.2019 •
Mathematics
The equation of a parabola is given.y=1/8x^2+4x+20 what are the coordinates of the focus of the parabola?
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Ответ:
y = 1/8(x + 16)^2 - 12
so the vertex is at (-16,-12) and the x coordinate of the focus will be -16)
The focus will be at (-16, k + p) Here k = -12 from the vertex equation and p = 1 / 4a where a = 1/8 so p = 1 / 1/2 = 2 So k + p = -12 + 2 = -10
So the coordinates of the focus are (-16, -10) answer
Ответ:
x= -7
Step-by-step explanation:
7(x+4)=3x+12x-5
7x+28=4x+7
-4x -28 -4x -28
3x=-21
/3 /3
x=-7