The equation of like ef is y= -1/2x + 6. write an equation of a line parallel to line ef in slope intercept form that contains point (0,-2)

  y = -1/2x -2

Step-by-step explanation:

The slope-intercept form of the equation for a line is ...

  y = mx + b

Comparing this to the equation you are given, you find that the given equation describes a line with a slope of -1/2 and a y-intercept of +6. The parallel line will have the same slope, so m=-1/2.

The given point is the y-intercept of the line you want, so you can use that y-value directly as the "b" in the equation you want:

  y = -1/2x -2

Yes, Okay. But, what is it that you want to know?