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Amyra2003
10.03.2020 •
Mathematics
The equilibrium constant K for a certain reaction was measured as a function of temperature (in Kelvin). A plot of ln(K) versus 1/T for this reaction gives a straight line with a slope of 1.352 x 104 K and a y-intercept of -14.51. Determine the value of ΔH° for this reaction.
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Ответ:
- 1.124 x 10⁵ J = -1.124 x 10² kJ
Step-by-step explanation:
The change in Gibbs free energy is related to the equilibrium constant K by
ΔGº = - RTlnK
But, we also know that by definition
ΔGº = ΔHº - TΔSº
thus
ΔHº - TΔSº = - RTlnK
lnK = - ΔHº/RT + ΔSº/R
This equation has the form y = mx + b where m is the slope and b is the y intercept.
Therefore, a plot lnK versus 1/T will give us a straight line with slope , m= - ΔHº/R.
We know m = 1.352 x 10⁴ K
so we can solve for ΔHº
ΔHº = - mR = 1.352 x 10⁴ K x 8.314 J / K = - 1.124 x 10⁵ J = -1.124 x 10² kJ
Ответ:
15784
i have no idea i just put all the numbers together this probably didn't help at all but ehh i tried