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SassyBanana
05.10.2019 •
Mathematics
The faces of a cube are numbered 1-6. if the cube is tossed once what is the probability that a prime number or a number divisible by 2 is obtained
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Ответ:
Prime Numbers 2, 3, 5
Divisible by 2 - 2, 4, 6
One is NOT a prime number.
So, there are 5 out of 6 numbers that are even or are prime.
This leaves only 1 number that isn't.
So, the probability is 5/6 that the number rolled will be prime or even.
Step-by-step explanation:
Ответ:
Part A
f(d) = 11.79
11.79=11(1.01)^d
(1.01)^d = 11.79/11
(1.01)^d = 1.071818
d = log 1.071818 /log 1.01
d = 6.97
Part B
y- intercept is obtained when domain = 0
d = 0 ⇒ f(0) = 11(1.01)^0 = 11*1 = 11
f(d) = 11
Part C
Average rate of change
Δf/Δd=
(f(7) - f(2)) / (7 - 2) =
(11(1.01)^7 - 11(1.01)^2) / 5 =
0.57 / 5 =
0.114
Step-by-step explanation: