The fifth graders were given sandwiches for lunch during your field trip nathan ate 5 out of 6 leroy ate 7 out of 8 of his sandwiches of his sandwich and sophia at 5 out of 8 of her sandwiches. who is the greatest amount of their sandwich

Leroy ate the most of his sandwich

Step-by-step explanation:

convert all the the fractions to percentages

Step-by-step explanation:

The fifth graders were given sandwiches for lunch during their field trip. Nathan ate 5/6 of his sandwich, Leroy ate 7/8 of his sandwich, and Sofia ate 5/8 of her sandwich. Who ate the greatest amount of their sandwich? ... Nathan ate 20/24, Leroy ate 21/24, and Sofia ate 15/24 meaning Leroy ate the most.

1a. Mean pulse rate for A = 60.5

1b. Range for A = 62

2a. Mean pulse rate for B = 73

2b. Range for B = 45

Step-by-step explanation:

1a. Determination of the mean pulse for patient A.

Data => 17, 16, 70, 69, 70, 75, 78, 70, 71, 69

Mean =?

The mean pulse rate for patient A can be obtained as follow:

Summation of data = 17 + 16 + 70 + 69 + 70 + 75 + 78 + 70 + 71 + 69

Summation of data = 605

Number of data = 10

Mean = summation of data / number of data

Mean = 605 / 10

Mean pulse rate for A = 60.5

1b. Determination of the range for patient A

Data => 17, 16, 70, 69, 70, 75, 78, 70, 71, 69

Range =?

Range = Highest – Lowest

Highest = 78

Lowest = 16

Range = Highest – Lowest

Range = 78 – 16

Range for A = 62

2a. Determination of the mean pulse for patient A.

Data => 59, 92, 60, 80, 71, 65, 50, 88, 95, 70

Mean =?

The mean pulse rate for patient B can be obtained as follow:

Summation of data = 59 + 92 + 60 + 80 + 71 + 65 + 50 + 88 + 95 + 70

Summation of data = 730

Number of data = 10

Mean = summation of data / number of data

Mean = 730 / 10

Mean pulse rate for B = 73

2b. Determination of the mean pulse for patient B.

Data => 59, 92, 60, 80, 71, 65, 50, 88, 95, 70

Range =?

Range = Highest – Lowest

Highest = 95

Lowest = 50

Range = Highest – Lowest

Range = 95 – 50

Range for B = 45