Mathematics: The figure below shows a shaded rectangular region inside a large rectangle: ( idk on how to submit a picture but i ll explain it.) the picture is a gray square that is 7 inches wide by 3 inches long. that gray square is inside a lighter square. the lighter square is 10 units long by 5 inches) is much appreciated! what is the probability that a point chosen inside the large rectangle is not in the shaded region? select one: a. 42% b. 58% c. 72% d. 84%

teamsStep-by-step explanation:Let s do it by parts. Let s consider a fact: there has to be only one winner. After six games:So, Since it s a decreasing Geometric Sequence (we have to lead to one winner), and each match two teams play, the beaten one leaves the championship.a) Explicit Rule (Formula):That s to say the tournament started with 32 teamsb) Recursive RuleIf we have the first term of the Geometric Sequence we can recursively find the subsequent terms. The Recursive Rule is useful when...

The figure below shows a shaded rectangular region

Ответ:

jaqsway34

12.01.2022

Mathematics

b. 58%

Step-by-step explanation:

Calculate the area of the entire rectangle using the formula A = lw.

The lowercase "L" is for length.

"w" is for width.

The lighter square is 10 units long by 5 inches wide.

A = lw

A = (10 in)(5 in) Multiply

A = 50 in²

Calculate the area for the shaded rectangle, 7 inches by 3 inches.

A = lw

A = (7 in)(3 in) Multiply

A = 21 in²

Calculate the area for the non-shaded region by subtracting the shaded area from the total area.

50 in² - 21 in² = 29 in²

The chance that a point in the large rectangle will NOT be in the shaded region is 29/50.

Convert this fraction to decimal form by using a calculator. Divide the top number by the bottom number.

29/50 = 0.58

0.58 is in decimal form. To convert it to a percentage, multiply the number by 100.

0.58 = 58%

Therefore the probability that a point chosen inside the large rectangle is not in the shaded region is 58%.

The figure below shows a shaded rectangular region inside a large rectangle: ( idk on how to submit

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Ответ:

samuelerlikhman

28.11.2021

Mathematics

teams

Step-by-step explanation:

Let's do it by parts.

Let's consider a fact: there has to be only one winner. After six games:

So, $a_{6}=1$

Since it's a decreasing Geometric Sequence (we have to lead to one winner), and each match two teams play, the beaten one leaves the championship.

$r=(\frac{1}{2})$

$a_{1}=?$

a) Explicit Rule (Formula):

$a_{6}=1,a_{1}=?r=\frac{1}{2}\\1=a_{1}\left ( \frac{1}{2} \right )^{6-1}\\1=a_{1}\left ( \frac{1}{2} \right )^{5}\\1=\frac{a_{1}}{32}\\a_{1}=32$

That's to say the tournament started with 32 teams

$\{32,16,8,4,2,1\}$

b) Recursive Rule

If we have the first term of the Geometric Sequence we can recursively find the subsequent terms. The Recursive Rule is useful when we have the prior term and we need the following one. Also, to derive the explicit rule.

$a_{1}=32\\a_{n}=\left ( \frac{1}{2} \right )a_{n+1}\\a_{2}=\left ( \frac{1}{2} \right )32=16\\a_{3}=\left ( \frac{1}{2} \right )16=8\\a_{4}=\left ( \frac{1}{2} \right )8=4\\a_{5}=\left ( \frac{1}{2} \right )4=2\\a_{6}=\left ( \frac{1}{2} \right )2=1\\$

$\{32,16,8,4,2,1\}$

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