The figure below shows circle with center o and two perpendicular diameters.

explain in a few sentences an outline of how you would use this figure to prove that abcd is a square. 25 points someone now

Hello,

Triangles OAB,BOC,COD,DOA are isocele and right , are thus equals and have the same hypothenus . The quadrilater ABCD is a diamond (having 4 sides equals) and its diagonals perpendicular is thus a square.

(Sorry for my poor english comming from France)

Triangles OAB, BOC, COD, DOA are isosceles and right, they are equal and have the same hypotenuse. The quadrilateral ABCD is a diamond (having 4 sides equals) and its diagonals perpendicular making this a square.

Step-by-step explanation:

45 45 90 special triangle

7√2 = √98

x² + y² = 98

x = y

x² + x² = 98

2x² = 98

x² = 49

x = 7

y = 7

ANSWER: c