The fish population of lake collins is decreasing at a rate of 3% per year. in 2004 there were about 1,300 fish. write an exponential decay function to model this situation. then find the population in 2010.

For this case we have a function of the form:
  Where,
 A: initial amount
 b: decrease rate
 x: time in years
 Substituting values we have:
 
 For 2010 we have:
 
 
 an exponential decay function to model this situation is:
 y = 1300 * (0.97) ^ x
 The population in 2010 is:
 y = 1083

1083 fish

Step-by-step explanation:

The fish population of Lake Collins is decreasing at a rate of 3% per year.

If starting population were about 1,300 in 2004 so the sequence will be

1,300, (1300 - 3% of 1300)..............

or 1300, 1261,.........

We know exponential function is modeled by

                   

Where         = population at time t.

                  = initial population

                   r = common ratio

                   n = time in years.

Common ratio (r) =

                            =

Then the function will be

Then population in year 2010 (after 6 years) will be

   = 1300(0.8329)

  = 1082.86 ≈ 1083 fishes

Mean girls or Clueless

Step-by-step explanation: