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micahwilkerson9495
11.10.2020 •
Mathematics
The formula determines the magnitude of an earthquake, where I is the intensity of the earthquake and S is the intensity of a “standard earthquake.” How many times stronger is an earthquake with a magnitude of 8 than an earthquake with a magnitude of 6? Show your work.
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Ответ:
An earthquake with a magnitude of 8 is 100 times stronger than an earthquake with a magnitude of 6.
Given the following data:
Magnitude A = 8Magnitude B = 6To determine how many times stronger is an earthquake with a magnitude of 8 than an earthquake with a magnitude of 6:
Mathematically, the magnitude of an earthquake is given by the formula:
Where:
I is the intensity of the earthquake.S is the intensity of a standard earthquake.For earthquake A:
For earthquake B:
For strength:
Strength = 100
Read more: link
Ответ:
100
Step-by-step explanation:
M = log(I/S)
The intensity of the first earthquake:
8 = log(I₁/S)
10⁸ = I₁/S
I₁ = 10⁸ S
The intensity of the second earthquake:
6 = log(I₂/S)
10⁶ = I₂/S
I₂ = 10⁶ S
The ratio is:
I₁/I₂ = (10⁸ S) / (10⁶ S)
I₁/I₂ = 100
It is 100 times stronger.
Ответ:
B. The axis of symmetry should be x=2
Step-by-step explanation: