The function below shows the number of car owners f(t), in thousand, in a city in different years t:

f(t) = 0.25t2 - 1.5t + 2.5

the average rate of change of f(t) from t = 5 to t = 8 is thousand per year

We are given the function f(t) = 0.25t2 - 1.5t + 2.5 and is asked in the problem to determine the average rate of change from t equal to 5 and t equal to 8. In this case, we substitute t with 5 and 8 first that is equal to 1.25 and 6.5, respectively. The rate of change is (6.5-1.25)/(8-5) equal to 1.75 thousand per year. 

The average rate of change of f(t) from t = 5 to t = 8 is 1.75 thousand per year.

Step-by-step explanation:

The given function is

We have to find the average rate of change of f(t) from t = 5 to t = 8.

Substitute t=5

Substitute t=8

The average  rate of change is defend as

Therefore the average rate of change of f(t) from t = 5 to t = 8 is 1.75 thousand per year.

27.6

Step-by-step explanation: i think this is correct but you basically just do 228 X 0.121 (the percent in decimal form) and you get 27.58800 and when rounded that becomes 27.6 sorry if it’s incorrect hope this helped :)