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aaronjewell3235
07.03.2020 •
Mathematics
The function gives the cost to manufacture x items. C(x) = 10,000 + 20x + 30,000 x ; x = 100 Find the average cost per unit of manufacturing h more items (i.e., the average rate of change of the total cost) at a production level of x, where x is as indicated and h = 10 and 1. (Use smaller values of h to check your estimates.) HINT [See Example 1.] (Round your answer to two decimal places.)
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Ответ:
Step-by-step explanation:
Average rate of change through the formula![=\frac{f\left ( b \right )-f\left ( a \right )}{b-a}](/tpl/images/0538/0602/dd7f3.png)
given that,
To find the average cost per unit of manufacturing
more items, the strategy is to apply the average rate of change to the function for
and the given
present.
when,![h](/tpl/images/0538/0602/8a40e.png)
![=10](/tpl/images/0538/0602/162f8.png)
Average cost per unit manufacturing![=\frac{C\left (100+10 \right )-C\left ( 100 \right )}{\left ( 100+10 \right )-\left ( 100 \right )}](/tpl/images/0538/0602/0ea18.png)
when![h=1](/tpl/images/0538/0602/aa07e.png)
Average cost per unit manufacturing![=\frac{C\left (100+1 \right )-C\left ( 100 \right )}{\left ( 100+1 \right )-\left ( 100 \right )}](/tpl/images/0538/0602/212f4.png)
if![h=0.1](/tpl/images/0538/0602/1df54.png)
Average cost per unit manufacturing![=\frac{C\left (100+0.1 \right )-C\left ( 100 \right )}{\left ( 100+0.1 \right )-\left ( 100 \right )}](/tpl/images/0538/0602/b20d2.png)
Therefore, it can be estimated that the average rate of change of the total cost to manufacture 100 items is $ 30020 per item (interpreted units).
Ответ:
Key features: the functions can not be parallels, this means that their respective slopes can not be equal or multiple to the other
Step-by-step explanation:
Take for instance 2 linear functions, and
If they intersect in some point in the space, say that is
Then (x1,y1)=(x3,y3), (x2.y2)= (x3,y3)
So, we can compare the two functions and get the following result;
It tells us that if M=m, we get an error, meaning that the functions are in fact parallels and there is no way that they meet in some point.
hope this helps!