The graph of a quadratic function has a vertex ar (3,-6). one point of the graph is (7,10). what is another point on the graph?

y + 6 = (x -3)^2

Step-by-step explanation:

Let's use the general form of the vertex equation of a quadratic:  y - k = a(x - h)^2.

Subst. 10 for y, 7 for x, -6 for k and 3 for h.  Then, 10 + 6 = a(7 - 3)^2, or

16 = a(4)^2, or 16 = a(16).  Thus, a = 1, and the equation of this particular parabola is:

y + 6 = (x -3)^2

3( -2x + 4)

let's equal the given soln to 0

3(-2x+4) = 0

-6x + 12 = 0

-6x + 12 - 12 = 0-12

-6x = -12

we divide both sides by -6

-6x/-6 = -12/-6

x = 2

Step-by-step explanation:

hope that will help you.