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Lilbre6999
20.02.2021 •
Mathematics
The half-life of hellium-5 is 7.6x10^-22 seconds, and the half-life of hellium-9 is 7x10^-21 seconds. Approximately how many times greater is the half-life of hellium-9 than that of helium-5?
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Ответ:
9.2 times greater
Step-by-step explanation:
Given that :
Half life :
Helium - 9 = 7x10^-21 seconds
Helium - 5 = 7.6x10^-22 seconds
To obtain the number of tunes helium - 9 half life is greater than helium - 5 ; we divide the half life of helium-9 by the half life of helium 5
7x10^-21 seconds / 7.6x10^-22 seconds
0.9210526 x 10^(-21 - (-22))
0.9210526 * 10^1
= 0.9210526 * 10
= 9.2105
About 9.2 times greater
Ответ: