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jonzyjones3114
16.11.2020 •
Mathematics
The half-life of the radioactive element unobtanium-43 is 10 seconds. If 48 grams of unobtanium-43 are initially present, how many grams are present after 10 seconds? 20 seconds? 30 seconds? 40 seconds? 50 seconds?
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Ответ:
At time, 10 seconds, the mass remaining is 24 grams
At time, 20 seconds, the mass remaining is 12 grams
At time, 30 seconds, the mass remaining is 6 grams
At time, 40 seconds, the mass remaining is 3 grams
At time, 50 seconds, the mass remaining is 1.5 grams
Step-by-step explanation:
Given;
initial mass of the radioactive element = 48 grams
half life, t = 10 seconds
time of decay (s) remaining mass of the radioactive element
0 48 grams
10 24 grams
20 12 grams
30 6 grams
40 3 grams
50 1.5 grams
600.75 grams
Thus;
At time, 10 seconds, the mass remaining is 24 grams
At time, 20 seconds, the mass remaining is 12 grams
At time, 30 seconds, the mass remaining is 6 grams
At time, 40 seconds, the mass remaining is 3 grams
At time, 50 seconds, the mass remaining is 1.5 grams
Ответ: