mwilliams457
06.07.2019 •
Mathematics
The height of a helicopter above the ground is given by h = 2.80t3, where h is in meters and t is in seconds. at t = 1.55 s, the helicopter releases a small mailbag. how long after its release does the mailbag reach the ground?
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Ответ:
H = 2.80t^3
h = 2.80 (1.55)^3 = 10.43
10.43 = 1/2 gt^2
10.43 x 2/9.8 = t^2
t = √2.12
= (Answer is 1.45)
Hope this helps!
Ответ:
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Step-by-step explanation: