The itsy-bitsy spider want to climb up the inside of a 1 foot water spout the itsy-bitsy spider can climb 3 3/4 inches each day before the rain comes down and washes her back one 1/4 inches each night the next day the sun comes up and dries up all the rain and the itsy-bitsy spider begins climbing again despite her discouraging progress the itsy-bitsy spider continues with this cycle until she makes it out the water spout how many days does it take the itsy bitsy spider to get out of the water spout

10 inches

Step-by-step explanation:

3 1\2-1 1/4= 2 1/2 inches each day

4× 2 1/2=10 inches

You have 15 dimes. You have 9 quarters. You have 12 nickels

Step-by-step explanation:

lets set some variables:

let "n" = the number of nickels

let "d" = the number of dimes

let "q" = the number of quarters

So, the total amount of money you have should be: $4.35 = 0.25q + 0.10d + 0.05n

Now let's look at the relationships between the coins:

"There are three fewer quarters than nickels": n - 3 = q

"six more dimes than quarters": q + 6 = d

So now you have three equations with three variables, all you need to do is solve.

first, you can substitute "n-3" for "q" (according to the 2nd equation) in the 1st and 3rd equation, you get:

You now only have two equations and two variables.

Simplify:

Now substitute "n+3" for "d" (according to the 2nd equation) in the 1st equation:

4.35=0.30n-0.75+0.10(n+3)

simplify:

4.35=0.30n-0.75+0.10n+0.30

4.35=0.40n-0.45

4.35+0.45=0.40n

4.80=0.40n

n=12

You have 12 nickels. Now sub "n" back into your equations to find the number of dimes and quarters:

n - 3 = q

12 - 3 = q

q = 9

You have 9 quarters.

q + 6 = d

9 + 6 = d

d = 15

You have 15 dimes.