Mathematics: The label on the car s antifreeze container claims to protect the car between −30°c and 130°c. to covert celsius temperature to fahrenheit temperature, the formula is c equals five ninths times the quantity f minus thirty two.. write a compound inequality to determine the fahrenheit temperature range at which the antifreeze protects the car. negative thirty is greater than five ninths times the quantity f minus thirty two is greater than one hundred thirty. negative thirty is less than five ninths

0.85×85=72.25. 72.25+85=157.25...

The label on the car s antifreeze container claims

Ответ:

ashton3952525

01.01.2022

Mathematics

F=C(9/5)+32

then sub both Celsius values in the formula

F=-30 (9/5)+32

=-22

F=130 (9/5)+32

=266

to the antifreeze protects the car between -22°F and 266°

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Ответ:

hayden6920

01.01.2022

Mathematics

$-22 ^\circ F \leq Temperature \leq 266 ^\circ F$

Step-by-step explanation:

We are given the following information in the question:

The car's antifreeze container claims to protect the car between −30°C and 130°C.

We have to convert this temperature into Fahrenheit.

The conversion is as follows:

$T_{(^\circ F)} = T_{(^\circ C)}\times \displaystyle\frac{9}{5} + 32,\\T_{(^\circ F)}\text{ is the temperature in Fahrenheit}\\T_{(^\circ C)}\text{ is the temperature in Celsius}$

Thus, the conversion takes place as follows:

$T_{(^\circ F)} = -30\times \displaystyle\frac{9}{5} + 32 = -22 ^\circ F\\\\T_{(^\circ F)} = 130\times \displaystyle\frac{9}{5} + 32 = 266^\circ F$

Compound inequality to determine the Fahrenheit temperature range at which the antifreeze protects the car:

$-22 ^\circ F \leq Temperature \leq 266 ^\circ F$

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