Mathematics: The largest possible fair dice is a disdyakis triacontahedron, which has 120 sides. What is the expected value, E(X), of rolling a disdyakis triacontahedron dice? a. 3.5 b. 60.5 c. 70 d. 1/120

The largest possible fair dice is a disdyakis triacontahedron,

Ответ:

Nigward666

21.01.2022

Assuming that the 120 faces have all numbers from 1 to 120 printed on them, we have a dice that can output all numbers between 1 and 120 with the same probability of 1/120.

So, the expected value is

$\displaystyle \sum_{i=1}^{120}i\cdot p(i) = \sum_{i=1}^{120}i\cdot \dfrac{1}{120}=\dfrac{1}{120}\sum_{i=1}^{120}i=\dfrac{1}{120}\dfrac{120\cdot 121}{2}=\dfrac{121}{2}=60.5$

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Ответ:

raeganwelch

24.12.2020

Mathematics

The answer is C because when t=9, the equations are equal, but the expressions themselves are not equal to each other.

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The largest possible fair dice is a disdyakis triacontahedron, which has 120 sides. What is the expected value, E(X), of rolling a disdyakis triacontahedron dice?

a. 3.5
b. 60.5
c. 70
d. 1/120

Ответ:

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