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Mochalav6675
06.05.2020 •
Mathematics
The length of a box is four-and-a-half inches more than its height. The width of the box is seven inches more than it's height. If the volume of the box is 4981.5 cubic inches, then what is the height of the box?
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Ответ:
The height of the box is 13.5 inches.
Step-by-step explanation:
Assume that the height of the box be x inches.
The length of the box four and half inches more than the height.
So, the height of the box is
The width of the box 7 inches more than its height
The width of the box is =(x+7) inches
So, the volume of the box is =Length×width×height
={x(x+7)+4.5(x+7)}x cubic inches
={x²+7x+4.5x+31.5}x cubic inches
=(x³+11.5x²+31.5x) cubic inches
But give that, the volume of the box is 4981.5 cubic inches.
According to the problem,
x³+11.5x²+31.5x=4981.5
⇒x³+11.5x²+31.5x-4981.5=0
⇒x³-13.5x²+25x²-337.5x+369x-4981.5=0
⇒x²(x-13.5)+25x(x-13.5)+369(x-13.5)=0
⇒(x-13.5)(x²+25x+369)=0
∴x=13.5 inches
The height of the box is 13.5 inches.
Ответ: