The length of a flower bed is four times as long

Ответ:

anahitah

23.01.2022

Mathematics

0.5625m squared

Step-by-step explanation:

3/8 multiplied by 4 = 1.5 + 3/8

make 3/8 into a decimal

3/8=0.375

0.375 multiplied by 1.5 = 0.5625

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Ответ:

Manuel2019

02.12.2021

Mathematics

$(1+\sec b)(\sec b - 1) = \dfrac{\sin b \sec b}{\cos b \csc b}$ focusing on the right-hand side: $\text{rhs} = \dfrac{\sin b \sec b}{\cos b \csc b}$ by definition, $\csc b = \frac{1}{\sin b}$ and $\sec b = \frac{1}{\cos b}$ . $\begin{aligned} \text{rhs} & = \dfrac{\sin b \sec b}{\cos b \csc b} \\ & = \dfrac{\sin b \cdot \frac{1}{\cos b}}{\cos b \cdot \frac{1}{\sin b}} \\ & = \dfrac{\frac{\sin b}{\cos b}}{ \frac{\cos b}{\sin b}} \end{aligned}$ this is really just division, which means multiply by reciprocal. $\begin{aligned} \text{rhs} & = \dfrac{\frac{\sin b}{\cos b}}{ \frac{\cos b}{\sin b}}\\ & = \dfrac{\sin b}{\cos b} \div \dfrac{\cos b}{\sin b} \\ & = \dfrac{\sin b}{\cos b} \cdot \dfrac{\sin b}{\cos b} \\ & = \dfrac{\sin^2 b}{\cos^2 b} \end{aligned}$ ======focusing on the left-hand side, expand out: $\begin{aligned} \text{lhs} & = (1 +\sec b)(\sec b - 1) \\ & = 1(\sec b - 1) +\sec b(\sec b - 1) \\ & = \sec b - 1 + \sec^2 b - \sec b \\ & = - 1 + \sec^2 b \\ & = \sec^2 b - 1 \end{aligned}$ this is an alternate form of a pythagorean identity.if we have $\sin^2 b + \cos^2 b = 1$ , dividing everything by secant gets us $\begin{aligned} \tfrac{\sin^2 b}{\cos^2 b} + 1 & =\tfrac{1}{\cos^2 b} \\ \tfrac{\sin^2 b}{\cos^2 b} + 1 & =\sec^2 b \\ \tfrac{\sin^2 b}{\cos^2 b} & = \sec^2 b - 1 \end{aligned}$ hence $\begin{aligned} \text{lhs} & = \sec^2 b - 1 \\ & = \frac{\sin^2 b}{\cos^2 b} \\ & = \text{rhs} \end{aligned}$ also, $\frac{\sin^2 b}{\cos^2 b} = \tan^2 b$

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The length of a flower bed is four times as long as it’s with if the width is 3/8 m what is the area

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