The length of a leg of an isoceles triangleis twice the length of the base. what is the minimum length of the base if the perimeter is at least 20 cm?

We have that the length of 1 leg is twice that of the base, and hence, the length of the other leg is also twice the length of the base.

Therefore by setting the length of the base as x we have that both legs have length 2x.

Therefore as the perimeter is the length of all the sides we have that 20cm = x + 2x + 2x = 5x

5x = 20
x = 4

The length of the base is 4cm

The answer would be "j"

Step-by-step explanation:

First, you would want to find the value of the original equation:

5(y + 2) + 4

Use order of operations and distribute the five.

5y + 10 + 4

5y +14

This is the value of the original equation

Now we can work through the other options, but because we already know the answer, lets see about that one.

5 x y + 5 x 2 + 4

Again, use order of operations.

Multiply first

5y + 10 + 4

and complete the equation

5y + 14, which equals our original equation.