The length of a new rectangle playing field is 8 yards longer than a quadruple the width if the perimeter of the rectangle playing field is 368 yards what are the dimensions

width = 35.2 yd; length = 148.8 yd

Step-by-step explanation:

Let the width = w.

The length is 8 yd more than 4 times the width.

length = 4w + 8

perimeter = 2(length + width)

perimeter = 2(4w + 8 + w)

perimeter = 2(5w + 8)

perimeter = 10w + 16

perimeter = 368 yd

10w + 16 = 368

10w = 352

w = 35.2

length = 4w + 8

length = 4(35.2) + 8

length = 148.8 yd

width = 35.2 yd; length = 148.8 yd

i need to see the whole question in order to answer you question sorry