The length of a new rectangular playing field is 6 yards longer than double the width. If the perimeter of the rectangular playing field is 294 yards what are the dimensions?

width = 47

Length = 100

Step-by-step explanation:

The perimeter of the rectangle has the formula

P = 2(L + W)

P = 2L + 2W

Length = 6 yards longer than double it's width.

Mathematically,

length = 6 + 2W

We put this into the formula for perimeter

P = 2(6+2W)+2W

294 = 12+4W+2W

294 = 12+6W

Collect like terms

294-12 = 6W

282 = 6w

Divide through by 6

W = 282/6

W = 47

This is the width

Remember length = 6 + 2(W)

So

Length = 6+2(47)

= 6+94

= 100

Width = 47

L = 100

These are the dimensions

9 I think but don’t take my word on it

Step-by-step explanation: