The length of a rectangle exceeds the breadth by 8 cm. Find the area of the rectangle, if its perimeter is 180 cm

2009cm^2

Step-by-step explanation:

Given data

let the length be L

and the width be w

so

w= x

L=x+8

P= 180cm

P= 2L+2W

180= 2(x+8)+2(x)

180= 2x+16+2x

collect like terms

180= 4x+16

180-16= 4x

164= 4x

x= 164/4

x=41

W= 41cm

L= 41+8

L= 49cm

A= L*W

A=49*41

A=2009cm^2

Hence the area is 2009cm^2

Step-by-step explanation:

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