The length of a rectangle is 1 yd less than double

Ответ:

glocurlsprinces

15.01.2022

So if say the width is "w", double that is 2*w, or 2w 1 unit less than that is 2w - 1, check the picture below

$\bf A=length\cdot width\qquad 
\begin{cases}
length = 2w-1\\
width = w\\
A=21
\end{cases}\implies 21=(2w-1)w
\\\\\\
21=2w^2-w\implies 0=2w^2-1-21
\\\\\\
0=(2w-7)(w+3)\implies 
\begin{cases}
0=2w-7\implies &\boxed{\frac{7}{2}=w}\\\\
0=w+3\implies &-3=w
\end{cases}$

since it cannot be a negative value, so... is not -3

what are the dimensions? well, length = 2w - 1, and w = well is above :)
The length of a rectangle is 1 yd less than double the width and the area of the rectangle is 21 yd^

The length of a rectangle is 1 yd less than double the width and the area of the rectangle is 21 yd^

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Ответ:

Ksedro1998

17.10.2022

Mathematics

B. 7

Step-by-step explanation:

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The length of a rectangle is 1 yd less than double the width and the area of the rectangle is 21 yd^2, what are the dimensions of the rectangle

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