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queentaryn13
09.12.2019 •
Mathematics
The length of a rectangle is 4 ya more than twice the width x. the area is 510 yd^2. find the dimensions of the given shape
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Ответ:
The dimensions of the rectangle are
length = 34 yards
width = 15 yards
Step-by-step explanation:
Given:
The shape is of rectangle,
Width of rectangle = x
Area of rectangle = 510 yd²
According to the given condition
Length of rectangle = 4 + 2x
To Find:
length =?
Width = ?
Solution:
We know that,
On substituting the given values we get
Which is a quadratic equation so we will apply splitting the middle term that is factorization we get
∴![x^{2}+ 17x -15x -255=0\\x(x+17)-15(x+17)=0\\(x-15)(x+17)=0\\\therefore x-15 =0\ or\ x+17=0\\\\\textrm{x cannot be negative i.e -17}\\\therefore x=15](/tpl/images/0410/5793/649ef.png)
∴ Width x = 15 yard
∴ Length = 4 + 2x = 4 +2 × 15 = 34 yard
The dimensions of the rectangle are
length = 34 yards
width = 15 yards
Ответ:
Step-by-step explanation:
First, create an equation for the price of the car for both dealerships:
Dealership A: y = 150x + 2500
Dealership B: y = 125x + 3000
where y is the total cost of the car and x is the number of months that have passed.
You know that y is equal to "150x + 2500" AND y is equal to "125x + 3000," so "150x + 2500" must be equal to "125x + 3000"
Now, just solve for x to find the number of months at which the total amount paid would be the same for both dealers:
So, after 20 months, the price of the car at both dealerships is the same. To find that price, just plug in 20 for x in one of the equations (because x was the number of months):
So, the car costs the same after 20 months, $5500 at either dealership.
Step-by-step explanation: