The length of a rectangle is 55 meters less than 44 times the width. if the perimeter is 150150 meters, find the length and the width of the rectangle.

They did not state exactly what the width or length is. So in this case, let's name the number of width to be x. And thus we can derive to the conclusion of,

Width : x
Length : x-44 (from the 1st sentence of question)
So, We all know that a rectangle has 2 Lengths and 2 widths. So we can derive the conclusion that,
2(x)+2(x-44)=150150
2x+2x-88=150150
4x-88= 150150
4x= 150150+88=150238
4x=150238
x= 150238÷4
=37559.5

(i) f(-3) = (-3)^2+2(-3)+1

So

9-6+1=10-6=4

(ii)f(5)= (5)^2+2(5)+1

so

25+10+1=36

(iii) Please check this question if it's correct or not