The length of a rectangle is 8 inches more than its width. the area of the rectangle is equal to
4 inches more than 2 times the perimeter. find the length and width of the rectangle.

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Ответ:

Bleejones00

22.07.2020

Mathematics

Hello,

Answer B (-5/3,-4/3)

Step-by-step explanation:

I am going to use the substitution 's method.

$\left\{\begin{array}{ccc}x+y&=&-3\\y&=&2x+2\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&2x+2\\x+2x+2&=&-3\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&2x+2\\3x&=&-5\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}x&=&-\dfrac{5}{3} \\\\y&=&2*(-\dfrac{5}{3})+2\\\end {array} \right.\\\\\\\boxed{\left\{\begin{array}{ccc}x&=&-\dfrac{5}{3} \\\\y&=&-\dfrac{4}{3}\\\end {array} \right.\\}$

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The length of a rectangle is 8 inches more than its width. the area of the rectangle is equal to4 inches more than 2 times the perimeter. find the length and width of the rectangle.