The length of a rectangle is 9 more than the width. the area is 286 square inches. find the length and the width of the rectangle

Width 13, Length = 22

Step-by-step explanation:

Let L = length and W = width

Given, length is 9 more than width, ie.

L = W + 9  > eq 1

Also given that area = 286 square inches.

Area of rectangle = length x width , or

286 = L x W   > eq 2

2 equations, 2 unknowns => we can solve this system of equations by substitution.

Substitute eq 1 into eq 2,

286 = (W + 9) x W

286 = W² + 9W

W² + 9W - 286 = 0 (solve quadratic equation using your favorite method)

w = 13 or w = -22 (impossible since width cannot be negative)

hence W = 13 (substitute this back into equation 1)

L = 13 + 9 = 22

Hope this helps you to understand, to do the problem and for future problems!

Step-by-step explanation:

All you have to do is take the numbers, add them, then divide them by how much there are. Once you did that if its a negative you just turn it positive bc its absolute.