Mathematics: The length of a rectangle is one foot more than twice its width if the area of the rectangle is 300 ft^2 find the dimensions of the rectangle someone explain this too me

The length of a rectangle is one foot more than

brianna8739

13.03.2022

Width of rectangle = 12 feet

Length of rectangle = 25 feet

Step-by-step explanation:

We are given the following information in the question:

Let x be the width of the rectangle.

We are given that:

$\text{Length} = 2\times \text{Width} + 1\\\text{Length} = 2x +1$

Area of rectangle = 300 square foot

Formula:

$\text{Area of rectangle} = \text{Length}\times \text{Width}$

Putting the values, we get,

$300 = x\times (2x +1)\\300 =2 x^2 + x\\2x^2 + x -300 = 0$

We use the quadratic formula to solve this quadratic equation:

$ax^2 + bx + c = 0\\\\x = \displaystyle\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Using the quadratic formula:

$2x^2 + x -300 = 0\\\\x = \displaystyle\frac{-1 \pm \sqrt{1+2400}}{4} = \displaystyle\frac{-1 \pm 49}{4}\\\\x = 12,\frac{-25}{2}$

Considering the positive value of x

Width of rectangle = 12 feet

Length of rectangle = 2x + 1 = 25 feet

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ihatemylife0

12.01.2021

( 3 , 0 ) ( 0 , − 6)a = 12 + 3y/ 16

Step-by-step explanation:

Add 3 to both sides

16a-3y+3y=12+3y

Simplify

16a=12+3y

Divide both sides by 16

16a/16 = 12/16 + 3y/ 16

a= 12+ 3y/16

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