kimhayleeshook50
26.02.2020 •
Mathematics
The length of Hillcrest Garden is 6 feet more than its width. A 3-foot wide walkway surrounds the outside of the garden. The total area of the walkway is 288 square feet. Find the dimensions of the garden.
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Ответ:
The dimensions of the garden would be 18 feet and 24 feet.
Step-by-step explanation:
Let the width of garden be 'x'.
Let the length of garden be
Since there is 3 foot wide walkway surrounds the outside the garden.
Area of walkway = 288 square feet
So, According to question, it becomes,
Width = 18+6 =24 feet
Hence, the dimensions of the garden would be 18 feet and 24 feet.
Ответ:
is this the full question