The length of the rectangle is 4 times the height. the area of the triangle is 63 cm2. find the width. round to the nearest tenth of an inch

area = l x h

l=4h

area = 4h x h = 4h^2

4h^2 =63

63/4 = 15.75

h^2 = 15.75

sqrt(15.75)=h

h = 3.968cm

rounded to nearest tenth would be 4.0cm

check L=4(4) = 16 x 4 = 64 ( since it was round 64 is pretty close to 63)

y=1/2x+4

Step-by-step explanation:

1 square down 2 square to the side you put that in a fraction 1/2 which is the gradient and the y-intercept is what passes through y which is 4