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Greatthinker2000
24.11.2020 •
Mathematics
The m<1=4x-30 and the m<5=2x+50. Find m<1 and m<7.
A. M<1=130 and M<7=130
B. M<1=130 and M<7=50
C. M<1=50 and M<7=50
D. M<1=50 and M<7=130
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Ответ:
D) m<1 = 50 m<7 = 130
Step-by-step explanation:
Lets set up the equation!
We know m<4 is 4x-30 and the m<5 is 2x + 50 due to alternate interior angles they are congruent so we can forge an equation, all we do is set them equal to each other!
4x-30 = 2x+50
Add 30 to both sides
4x = 2x +80
Subtract 2x from both sides.
2x = 80
Divide both sides by 2
x = 40
Now that we know x we can just plug it into the expression of m<4 to find m<1
4x-30
4(40)-30
80 - 30
50
m<4 = 50
Because m<1 and m<4 are vertical angles they are congruent!
m<1 = 50
We also know m<4 and m<5 are congruent so m<5 = 50 as well.
Because <7 is supplementary to <5 we know that the sum of both angles amount to 180.
x represents m<7
50 + x = 180
Now we solve by subtraction 50 from both sides
x = 130
m<7 = 130
Brainliest is appreciated!
Ответ:
Since the beginning number -5x^2 is negative, it will open down.