RivvytheFanboy6510
25.01.2020 •
Mathematics
The number of bacteria in a culture is growing at a rate of 1500e^(3t/4) per unit of time t. at t=0, the number of bacteria present was 2000. find the number present at t=4.
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Ответ:
P=2000 2000=2000e^0+C
C=0
P(t)=2000e^{3t/4}
P(4)=2000e^3
P(4)=40171.1
Ответ:
The exponential growth formula is y = a(1+r)^x
y = 100(1+.11)^t