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algahimnada
21.12.2019 •
Mathematics
The number of e.coli bacteria cells in a pond of stagnant water can be represented by the function below, where a represents the number of e.coli bacteria cells per 100 ml of water and t represents the time, in years, that has elapsed.
a(t)=136(1.123)^4t
based on the model, by approximately what percent does the number of e.coli bacteria cells increase each year?
a.
60%
b.
59%
c.
41%
d.
40%
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Ответ:
Explanation:
The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:
The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:
Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.
Ответ:
The area of a circle is pi times the radius squared (A = π r²).
Step-by-step explanation:
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