The number of students enrolled in a new course as a function of time can be represented by the function. f(x)=(4)^x −1 what is the average increase in the number of students enrolled per hour between hours 2 and 4? enter your answer in the box.

120

Step-by-step explanation:

We are given that the function for the number of students enrolled in a new course is .

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

,

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) = = 255 and the number of students enrolled at 2 = f(2) = = 15

So, the average increase = = = 120.

Hence, the average increase in the number of students enrolled is 120.

is there a 120 if so i took  the test

Step-by-step explanation:

x1 =2-5i*sqrt(2)

x2 =2+5i*sqrt(2)

Step-by-step explanation:

-x^2 +4x-54=0 (quadratic equation)

a=-1, b=4, c=-54

x1=(-b+sqrt(b^2-4ac))/2a

x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)

x1=(-4+sqrt(16-216))/(-2)

x1 =(-4+sqrt(-200))/(-2)

x1 =(-4+sqrt(200i^2))/(-2) i^2=-1

x1 =(-4+sqrt(100*2*i^2))/(-2)

x1 =(-4+10i*sqrt(2))/(-2)

x1 =2-5i*sqrt(2)

x2 =(-b-sqrt(b^2-4ac))/2a

x2 =(-4-10i*sqrt(2))/(-2)

x2 =2+5i*sqrt(2)