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tornadowolfcosplay
11.12.2019 •
Mathematics
The owner of a computer repair shop has determined that their daily revenue has mean $7200 and standard deviation$1200. the daily revenue totals for the next 30 days will be monitored. what is the probability that the mean daily revenuefor the next 30 days will exceed $7500
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Ответ:
The probability that the mean daily revenue for the next 30 days will exceed $7500 is 0.0855
Step-by-step explanation:
It has been given that
Now, the formula for z-score of a normal distribution is given by
Substituting the known values, we get
Simplifying, we get
Now, we have to find that the daily revenue for next 30 days will exceed $7500.
Thus, we have to find
P(z>1.369238)
From the normal distribution table, we have
P(z>1.369238)= 0.0855
Therefore, required probability is 0.0855
Ответ:
61
Step-by-step explanation:
1/5 = .2
so you do 12.2 / .2 which gives you 61