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terrieldixon
27.08.2019 •
Mathematics
The owner of a restaurant is reviewing customer complaints. in a random sample of 227 complaints, 57 complaints were about the slow speed of the service. create a 95% confidence interval for the proportion of complaints that were about the slow speed of the service. use excel to create the confidence interval, rounding to four decimal places.
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Ответ:
Step-by-step explanation:
Given :The owner of a restaurant is reviewing customer complaints. In a random sample of 227 complaints, 57 complaints were about the slow speed of the service.
To Find :Create a 95% confidence interval for the proportion of complaints that were about the slow speed of the service.
Solution:
n = 227
x = 57
Formula of confidence for proportion:
to ![\widecap{p}+z_{\frac{\alpha}{2}}\sqrt{\frac{\widecap{p}\widecap{q}}{n}}](/tpl/images/0200/9043/91c7f.png)
z at 95% is 1.96
Substitute the values in the formula :
Confidence for proportion:
to ![0.25+1.96\sqrt{\frac{0.25 \times 0.75}{57}}](/tpl/images/0200/9043/6b78f.png)
Confidence for proportion:
to ![0.3624](/tpl/images/0200/9043/e9840.png)
Hence 95% confidence interval for the proportion of complaints that were about the slow speed of the service is
to ![0.3624](/tpl/images/0200/9043/e9840.png)
Ответ:
3 rolls of dimes and 8 rolls of nickels
hope it helps :]