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lizdeleon248
09.01.2020 •
Mathematics
The owner of a shopping mall wants an estimate of the lengthof
time shoppers spend in the mall. the estimate is to be within
5minutes of the true time, with a 98% confidence level. the
estimateof the standard deviation of the length of time spent in
the mallis 20 minutes. how large a sample will be needed?
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Ответ:
A sample size of at least 87 will be needed.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 2.325](/tpl/images/0447/6656/b0bb6.png)
Now, find M as such
In which
is the standard deviation of the population and n is the size of the sample.
In this problem, we have that:
So
A sample size of at least 87 will be needed.
Ответ:
a. 6^2 = 2^2 + 3^2
36 = 4 + 9
36 = 13
Therefore this is not a Pythagorean triple
b.5^2 = 4^2 + 3^2
25 = 16 + 9
25 = 25
Therefore this is a phythagorean triple