The owner of a video store has determined that the cost c, in dollars, of operating the store is approximately given by f(x) = 2x2- 22x + 660, where x is the number of videos rented daily. find the lowest cost to the nearest dollar.

$600

Step-by-step explanation: The cost of the store is defined by the equation:

f(x) = 2x^2 - 22x + 660

Where x is the number of videos rented daily, if we want to find the minimum of a function, we need to see the point in wich the derivate is equal to zero, in this case we have:

f'(x) = 4*x - 22 = 0

x = 22/4 = 5.5

So if he rents 5.5, the total cost of the store is:

f(5.5) = 2*5.5^2 - 22*5.5 + 660 = 599.5 dollars

Rounding to the nearest dollar, we have a total minimal cost of 600 dollars

The coach should start recruiting players with weight 269.55 pounds or more.                                                    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

We have to find the value of x such that the probability is 0.15

Calculation the value from standard normal z table, we have,  

Thus, the coach should start recruiting players with weight 269.55 pounds or more.