The pacific halibut fishery has been modeled by the differential equation dy/dt= ky(1 - y/m) where y(t) is the biomass (the total mass of the members of the population) in kilograms at time t (measured in years), the carrying capacity is estimated to be m = 7 times 107 kg, and k = 0.78 per year. if y(0) = 2 times 107 kg, find the biomass a year later. (round your answer to two decimal places.) times 107 kg how long will it take for the biomass to reach 4 times 107 kg?

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kyahshayovvu24

23.12.2021

Mathematics

$\textrm{Number of gallons of paint required = }\frac{\textrm{Total Area Covered}}{\textrm{Area covered per gallon}}$

Step-by-step explanation:

Each gallon of paint covers $sq\textrm{ }ft$ . All sides of the room as well as the wall are of $8\textrm{ }ft\textrm{ }$ × $8\textrm{ }ft$ dimensions.

So, clearly, the total paint covers all the walls and the roof. So, we can infer that $\textrm{Total Area covered}=\textrm{ (Number of gallons of paint used) x}\textrm{ (Area covered per gallon)}$

$\textrm{Total Area covered = (4walls + 1 ceiling)\textrm{x}(Area of each wall)}$

$\textrm{Total Area covered = }8\textrm{ x }5\textrm{ x }5\textrm{ sq ft}$ $\textrm{ = }320\textrm{ sq ft }$

$\textrm{Number of gallons of paint required = }\frac{\textrm{Total Area Covered}}{\textrm{Area covered per gallon}}$ $\textrm{ = }\frac{320\textrm{ sq ft}}{40\frac{sq ft}{gallon}}\textrm{ = }8\textrm{ gallons}$

∴ Number of gallons of paint required = $8\textrm{ gallons}$

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