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taz64
07.06.2020 •
Mathematics
the perimeter of a pickleball court is 128 feet. The width is represented by x and the length is represented by 2x + 4. What are the actual dimensions of the pickleball court (length and width)?
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Ответ:
x=62.
Step-by-step explanation:
2x +4=128
2x=128-4
2x=124
x= 62
Ответ:
b < a with 6 ⇒ b = a - 6 (2)
(1), (2) ⇒ a + a - 6 = 60 ⇒ a + a = 60 + 6 ⇒ 2a = 66 ⇒ a + 66:2 ⇒
⇒ a = 33 (3)
(2), (3) ⇒ b = 33 - 6 ⇒ b = 27
So, the numbers are : a = 33, b = 27