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angelinaavila06
02.09.2020 •
Mathematics
The perimeter of a playing field for a certain sport is 334ft. The field is a rectangle, and the length is 47 ft longer than the width. Find the dimensions.
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Ответ:
The dimensions of the rectangle = 60ft by 107ft
Where 60 ft = Width of the playing field
107ft = Length of the playing field
Step-by-step explanation:
A playing field is Rectangular is shape, hence,
The formula for Perimeter of a rectangle = 2(L + W)
P = 334 ft
L = 47 + W
W = W
Hence we input these values in the formula and we have:
334 = 2(47 + W + W)
334 = 2(47 + 2W)
334 = 94 + 4W
334 - 94 = 4W
240 = 4W
W = 240/4
W = 60
There fore, the width of this playing field = 60 ft
The length of this rectangle is calculated as:
47 + W
47 + 60
= 107 ft
The length of this playing field = 107ft
Therefore the dimensions of the rectangle = 60ft by 107ft
Ответ:
Terry was charged for 4.5 hours of labor.
Step-by-step explanation:
50x + 150 = 375
Where x = hours
50x = 375 - 150
50x = 225
Divide both sides by 50 to isolate x
x = 4.5