The perimeter of a rectangle is 50ft. If the length is one more than twice the width, what is the length, width and area?

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Step-by-step explanation:

Let the width of the rectangle be x

Since the length is one more than twice the width. Therefore, the length will be: = 2x + 1

Perimeter of a rectangle = 2(length + breadth)

50 = 2(2x + 1 + x)

50 = 2(3x + 1)

50 = 6x + 2

6x = 50 - 2

6x = 48

x = 48/6

x= 8

Width = 8ft

Length = 2x + 1 = 2(8) + 1 = 16 + 1 = 17ft

Area = Length × Width = 17 × 8 = 136ft^2

12 is the correct answer

Step-by-step explanation: