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13.02.2021 •
Mathematics
The perimeter of a rectangular field is 340 yd. The length is 50 yd longer than the width. Find the dimensions.
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Ответ:
width = 60 yd
and Length= 110 yd
Step-by-step explanation:
Step 1
Perimeter of rectangle field is given as 2 ( L+ b)
Let the width be represented as x
'and length which is 50 yd longer than the width be
=x+ 50
such that the Perimeter with 340 yd can be expressed as
Perimeter = 2 ( L+ b) = 2L + 2B
Step 2---Solving
Perimeter = 2L + 2B
340 = 2(X+ 50) + (2 x)
340 = 2X+ 100 + 2X
340=4X + 100
340-100=4X
240= 4X
X= 240/4
X= 60
Width = x = 60 yards
;Length = 50 + x= 50 + 60 = 110yards
Ответ:
Width=60 yd
length=110 yd
Step-by-step explanation:
Ответ:
The function to represent the increasing number of rabbits per yer is
Solution:
The number of rabbits released each year is 8.
During 0 year, there will be 8 rabbits;
During year 1, the number of rabbits will be (or)
Similarly, during the year 2, the number of rabbits will be or
So, according to the pattern we can conclude that the function would be
where x is the number of years.
On year 4, the total number of rabbits will be = 128