The perimeter of rectangle ABCD is four times greater than the perimeter of rectangle EFGH.

What is the perimeter of ABCD?

*Perimeter = 2L + 2W*

4x2−x+12

4x2−x+16

8x2−2x+24

16x2−4x+48

16x2−12x+48

4x2−3x+12

The answer to your question is 8x² - 2x + 24

Step-by-step explanation:

Data

EF = x² - x + 6

GF = x² + 1/2x

Perimeter

P = 2L + "W

But the condition is that the perimeter of rectangle ABCD is twice the perimeter of rectangle EFGH so.

Perimeter of EFGH = 4L + 4W

Substitution

Perimeter = 4(x² - x + 6) + 4(x² + 1/2x)

Simplification

Perimeter = 4x² - 4x + 24 + 4x² + 2x

                 = 8x² - 2x + 24

Choices 4 & 2

Step-by-step explanation:

-7x+14> -3x -6

-14. -14

-7x> -3x -20

+3x. +3x

-4x> -20

Divide eah side by negative four with gets u 5 but since you divided by a negative you have to flip the sign

x<5 instead of x>5

So 5 and 10 are greater than x making them the answers to the inequality