Mathematics: The point (-7, -24) is on the terminal ray of angle θ which is in standard position. a student found the six trigonometric values for angle θ. the student’s answers are shown

The point (-7, -24) is on the terminal ray of angle

Ответ:

davestrider404

13.03.2022

The student wrongly calculated the value of $\rm tan\theta$ , $\rm sin\theta$ , $\rm cosec\theta$ , and $\rm cot\theta$ and this can be determined by using the Pythagorean theorem and trigonometric functions.

GIven :

The point (-7, -24) is on the terminal ray of angle θ which is in standard position.

To determine the trigonometric function first determine the value of the hypotenuse and to determine the value of the hypotenuse, the Pythagorean theorem can be used.

$\rm H^2 = P^2 + B^2$

where H is the hypotenuse, B is the base, and P is the perpendicular.

Now, substitute the value of known terms in the above equation.

$\rm H^2 = 7^2+24^2$

$\rm H^2=49+576$

$\rm H^2 = 625$

H = 25

Now, the values of the trigonometric functions are as follows:

$\rm cos\theta=\dfrac{-7}{25}$

$\rm sin\theta=\dfrac{-24}{25}$

$\rm tan\theta=\dfrac{24}{7}$

$\rm cosec\theta=\dfrac{25}{-24}$

$\rm sec\theta=\dfrac{25}{-7}$

$\rm cot\theta=\dfrac{7}{24}$

The student wrongly calculated the value of $\rm tan\theta$ , $\rm sin\theta$ , $\rm cosec\theta$ , and $\rm cot\theta$ .

For more information, refer to the link given below:

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Ответ:

ddaaaeeee2960

13.03.2022

Mathematics

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\quad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\\\\\\
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\qquad 
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\quad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}\\\\
-------------------------------$

$\bf (\stackrel{a}{-7}~~,~~\stackrel{b}{-24})
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{(-7)^2+(-24)^2}\implies c=\sqrt{49+576}\implies c=\sqrt{625}
\\\\\\
c=25\impliedby hypotenuse\\\\
-------------------------------$

$\bf sin(\theta )=\cfrac{-24}{25}\qquad cos(\theta )=\cfrac{-7}{25}\qquad \qquad tan(\theta )=\cfrac{-24}{-7}\implies \cfrac{24}{7}
\\\\\\
cot(\theta )=\cfrac{-7}{-24}\implies \cfrac{7}{24}\qquad \qquad sec(\theta )=\cfrac{25}{-7}\qquad csc(\theta )=\cfrac{25}{-24}$

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Ответ:

zhellyyyyy

22.02.2022

Mathematics

The way I did this was determine the proofreaders’ page/hour rate. 200/6 is 33.33, while 200/9 is 22.22. 55.55 in total. 55.55/hour, combined, means that this hourly rate would need to multiply to fit in three hours. Thus, we multiply 55.55 by three, giving us 166.65. This is not two hundred, meaning you need more time, or better proofreaders.

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The point (-7, -24) is on the terminal ray of angle θ which is in standard position. a student found the six trigonometric values for angle θ. the student’s answers are shown

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