The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). what is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2

Correct equation of the line is

The standard form is: Ax + By = C.

30.49 m

Step-by-step explanation:

To obtain the maximum height, we solve for the value x when dy/dx = 0.

Since, y = -5x² + 40x + 20

dy/dx = d[-5x² + 40x + 20]/dx

dy/dx = -10x + 40

Since dy/dx = 0,

-10x + 40 = 0

-10x = -40

x = -40/-10

x = 4

Substituting x = 4 into the equation for y, we have

y = -5x² + 40x + 20

y = -5(4)² + 40(4) + 20

y = -5(16) + 160 + 20

y = -80 + 160 + 20

y = 80 + 20

y = 100 ft

Since y is in feet, we convert to meters.

Since 1 m = 3.28 ft, 100 ft = 100 ft × 1 m/3.28 ft = 30.49 m

So, the maximum height, in meters  reached by the projectile is 30.49 m