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mistiehaas
20.10.2020 •
Mathematics
The polynomial p(x)=x^3+7x^2-36p(x)=x 3 +7x 2 −36p, left parenthesis, x, right parenthesis, equals, x, cubed, plus, 7, x, squared, minus, 36 has a known factor of (x+3)(x+3)left parenthesis, x, plus, 3, right parenthesis. Rewrite p(x)p(x)p, left parenthesis, x, right parenthesis as a product of linear factors. p(x)=
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Ответ:
(x-2)(x+3)(x+6)
Step-by-step explanation:
Given the polynomial function p(x)=x^3+7x^2-36
We are to write it as a product of its linear factor
Assuming the value of x that will make the polynomial p(x) to be zero
Let x = 2
P(2) = 2³+7(2)²-36
P(2) = 8+7(4)-36
P(2) = 8+28-36
P(2) = 0
Since p(2) = 0 hence x-2 is one of the linear factors
Also assume x = -3
P(-3) = (-3)³+7(-3)²-36
P(-3) = -27+7(9)-36
P(-3) = -27+63-36
P(-3) = 36-36
P(-3) = 0
Since p(-3) = 0, hence x+3 is also a factor
The two linear pair are (x-2)(x+3)
(x-2)(x+3) = x²+3x-2x-6
(x-2)(x+3) = x²+x-6
To get the third linear function, we will divide x^3+7x^2-36 by x²+x-6 as shown in the attachment.
x^3+7x^2-36/x²+x-6 = x+6
Hence the third linear factor is x+6
x^3+7x^2-36 = (x-2)(x+3)(x+6)
Ответ:
x^3 + 7x^2 -36 = (x + 3)(x-2)(x + 6)
Step-by-step explanation:
Here we want to rewrite the polynomial
P(x) = x^3 + 7x^2 - 36
As a product of linear factors given that we have one of the roots already as (x + 3)
What we shall do here is to divide the polynomial by x + 3
Please check attachment for long polynomial division
From the division, the other factor is x^2 + 4x -12
So we can rewrite the polynomial as;
x^3 + 7x^2 -36 = (x + 3)(x^2 + 4x -12)
So let’s now write x^2 + 4x -12 as a product of its linear factors
x^2 + 4x -12 = x^2 + 6x -2x -12
= x(x + 6)-2(x + 6)
so we have;
(x -2)(x + 6)
Therefore;
x^3 + 7x^2 -36 = (x + 3)(x-2)(x + 6)
Ответ:
a i think
Step-by-step explanation: